Question 100359This question is from textbook texas algebra 2
: how do you write and graph an equation for
(A LINE PASSING) through (-2,1) and parallel to y=-2/3x-4
This question is from textbook texas algebra 2
Answer by oberobic(2304)   (Show Source):
You can put this solution on YOUR website! Parallel lines have the same slope (by definition), so the slope of the line passing through the point(-2,1) will have to have slope = -2/3. We know that the line is sloping down to the right because the slope is negative. The slope is also the change in y divided by the change in x, so for each change of 3 on the x-axis, the y value decreases by 2 (that is, -2/3). To define a line, we need another point to pair with (-2,1).
We know that the general equation for a line is  . We know one y and one x, but we don't know b, so we substitute what we know and solve that.
 so 
Recall the b is called the y-intercept, which tells us where the line crosses the y-axis when x=0. That gives us another coordinate pair: (0, -1/3). So the equation for the line is:
 .
|
|
|
