SOLUTION: solve each equation by addition method x/3-y=2 -x/2+3y/2=-3

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Question 1000482: solve each equation by addition method
x/3-y=2
-x/2+3y/2=-3
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

x%2F3-y=2.....eq.1...both sides multiply by 3
-x%2F2%2B3y%2F2=-3......eq.2...both sides multiply by 2
------------------
x-3y=6.....eq.1
-x%2B3y=-6
-----------------add
x-3y-x%2B3y=6-6
0=0
So we're left with
0=0

which means any x or y value will satisfy the system of equations. So, there are an infinite number of solutions (they coincide with each other) and this system is dependent.