SOLUTION: Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line. (−3,5);y=−12x+4

Algebra ->  Graphs -> SOLUTION: Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line. (−3,5);y=−12x+4      Log On


   

Question 1000191: Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line.
(−3,5);y=−12x+4
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line


Since any two parallel lines have the same slope we know the slope of the unknown line is -12 (its from the slope of y=-12%2Ax%2B4 which is also -12). Also since the unknown line goes through (-3,5), we can find the equation by plugging in this info into the point-slope formula

Point-Slope Formula:

y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is the slope and (x%5B1%5D,y%5B1%5D) is the given point



y-5=-12%2A%28x%2B3%29 Plug in m=-12, x%5B1%5D=-3, and y%5B1%5D=5



y-5=-12%2Ax%2B%2812%29%28-3%29 Distribute -12



y-5=-12%2Ax-36 Multiply



y=-12%2Ax-36%2B5Add 5 to both sides to isolate y

y=-12%2Ax-31 Combine like terms

So the equation of the line that is parallel to y=-12%2Ax%2B4 and goes through (-3,5) is y=-12%2Ax-31


So here are the graphs of the equations y=-12%2Ax%2B4 and y=-12%2Ax-31



graph of the given equation y=-12%2Ax%2B4 (red) and graph of the line y=-12%2Ax-31(green) that is parallel to the given graph and goes through (-3,5)