Tutors Answer Your Questions about Geometry proofs (FREE)
Question 704815: Triangle HGJ
If angle H = 90 degrees, GJ is greater than GH.
How is GJ greater than GH? H = 90 degrees, and a triangle has to equal 180 degrees, I don't understand how it can be greater than and not less than.
Click here to see answer by KMST(5347)  |
Question 717236: I was given a triangle, Labeled ABC, which is bisected by line BD, to create two smaller triangles, ABD and DBC. Given: BD is the perpendicular bisector of AC. Prove: Line DB bisects Angle ABC
What am I missing? I think it falls apart the last two reasons. :(
Statements / Reasons
Step 1
Line BD is the perpendicular bisector of Line AC / Given
Step 2
Angle ADB and Angle BDC are right angles / Def. of perpendicular lines
Step 3
Angle ADB is congruent to Angle BDC / Rt angles are congruent
Step 4
Line AD is congruent to Line DC / Def. of bisector
Step 5
Line DB is congruent to Line DB / Reflexive ppty of congruence
Step 6
Triangle ABD is congruent to Triangle DBC / SAS
Step 7
Angle ABD is congruent to Angle DBC / CPCTC
Step 8
Line DB bisects Angle ABC / CPCTC
Click here to see answer by lynnlo(4176) |
Question 717236: I was given a triangle, Labeled ABC, which is bisected by line BD, to create two smaller triangles, ABD and DBC. Given: BD is the perpendicular bisector of AC. Prove: Line DB bisects Angle ABC
What am I missing? I think it falls apart the last two reasons. :(
Statements / Reasons
Step 1
Line BD is the perpendicular bisector of Line AC / Given
Step 2
Angle ADB and Angle BDC are right angles / Def. of perpendicular lines
Step 3
Angle ADB is congruent to Angle BDC / Rt angles are congruent
Step 4
Line AD is congruent to Line DC / Def. of bisector
Step 5
Line DB is congruent to Line DB / Reflexive ppty of congruence
Step 6
Triangle ABD is congruent to Triangle DBC / SAS
Step 7
Angle ABD is congruent to Angle DBC / CPCTC
Step 8
Line DB bisects Angle ABC / CPCTC
Click here to see answer by solver91311(24713)  |
Question 718539: Given: Quadrilateral ABCD; E, F, G and H are midpoints of AD, AB, BC, and CD respectively.
Proof: EFGH is a parallelogram.
Hint: Draw diagonal AC. Using triangle ABC and triangle ACD, prove line segment FG is parallel to line segment HE. Prove line segment FG is congruent to line segment HE. therefore EFGH is a parallelogram
(I Have The Picture Of The Quadrilateral give and everything if it would help more...) just email me for it to
pistilo-12z@live.com
Click here to see answer by mananth(16949)  |
Question 720830: Hello there, I am hoping that you can help me with this geometry proof. I have been looking everywhere for an example, but have had no luck. I even checked geometry books out at our local library.
I believe that the problem is based on the Pythagorean Theorem Proof Using Similarity.
Given: ∆ ABC, AD bisects ∠BAC, and AE ≅ ED
Prove: AE/AC = BD/BC
The picture provided shows a triangle labeled ABC. AD bisects angle BAC. From point D there is another line that extends to the side of the triangle labeled AC, this point is labeled E. I am sorry that I am unable to attach a picture. Any help would be appreciated!
Click here to see answer by mananth(16949)  |
Question 724078: I am in need of help with proving the following:
GIVEN:
Line segment EG bisects angle DEF
Angle EDG is congruent to angle EFG
Prove: Triangle DGF is isosceles
Starting with the two given statments the next statements and reasons I have are:
Step 1
Line segment EG bisects angle DEF; Reason: Given
Step 2 Angle EDG is congruent to angle EFG; Reason: Given
Step 3
Triangle EDG is congruent to Triangle EFG;
Reason: ASA
Step 4 Line segment ED is congruent to line segment EF;
Reason: CPCTC
Step 5 Line segment EG is congruent to line segment EG;
Reason: Reflexive
Step 6
Triangle ABC is Isosceles;
Reason: Definition of Isosceles
Am I on the right track? Any help would be great. Thanks in advance!
Click here to see answer by KMST(5347)  |
Question 725853: Write a two-column proof.
Here is the image for the proof:

Lines JM, KN, and LO all intersect at point P. measure of angle KPL = 30 and measure of angle JPL = 90. Prove the measure of angle NPM = 60.
1. Lines JM, KN, LO intersect at point P, measure of angle JPL = 30, measure of angle JPL = 90. | Given
I really don't know where to go from there.
Click here to see answer by mananth(16949)  |
Question 731869: Can you please help me on my homework? I'm not very good at proofs.
Given: K is the midpoint of HL and MJ. HL and MJ cross each other to create two triangles connecting at point K.
Prove: Triangle HJK is congruent to Triangle LMK.
Click here to see answer by fcabanski(1391) |
Question 731826: Provide the reasons for the proof.
Given: m angle 1 = m angle 2
Prove: (line over)AC(up-side down T)(line over)BD
Statements:
a. m angle 1 = m angle 2
b. Angle 1 is supplementary to angle 2
c. m angle 1 + m angle 2= 180 degrees
d. m angle 1 + m angle 2 +180 degrees
2(m angle 1)= 180 degrees
e. m angle 1 = 90 degrees
f. angle 1 is a right angle
g.(line over)AC(up-side down T)(line over)BD
Reasons:
a. given
b. ?
c. ?
d. ?
e. ?
f. ?
g. ?
Click here to see answer by lynnlo(4176) |
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