SOLUTION: Retaken Geometry This Semester And Proofs were my biggest error last year, need help! 1. 1/2(4m+3)+1/3 2. 4(3r+1)-1/2(10r+6) 3. 1-3(2a+3b)-7(4-2a)+2 SOLVE 4. 2m+6(5-3

Algebra ->  Geometry-proofs -> SOLUTION: Retaken Geometry This Semester And Proofs were my biggest error last year, need help! 1. 1/2(4m+3)+1/3 2. 4(3r+1)-1/2(10r+6) 3. 1-3(2a+3b)-7(4-2a)+2 SOLVE 4. 2m+6(5-3      Log On


   

Question 910273: Retaken Geometry This Semester And Proofs were my biggest error last year, need help!
1. 1/2(4m+3)+1/3
2. 4(3r+1)-1/2(10r+6)
3. 1-3(2a+3b)-7(4-2a)+2
SOLVE
4. 2m+6(5-3m)+22=0
5. 1-3(2m+2)+2m=5
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

The following are completed by first using the Distributive Principle:

1. 1/2(4m+3)+1/3 

 2m + 3/2 + 1/3   Distributive Principle

0r 2m + 11/3  simplification 

2. 4(3r+1)-1/2(10r+6) 

12r + 4 - 5r - 3    Distributive Principle

0r 7r+1  simplification 

3. 1-3(2a+3b)-7(4-2a)+2 

1 - 6a - 6b -28 + 14a + 2   Distributive Principle

0r 8a - 6b -25   simplification 

4. 2m+6(5-3m)+22=0 

2m + 30 - 18m + 22 = 0 Distributive Principle

52 = 16m  Addition Property of Equality

52/16 = m  Multiplication  Property of Equality

m = 13/4  0r  3 1/4

5. 1-3(2m+2)+2m=5

1-6m - 6 + 2m = 5  Distributive Principle

-10 = 4m  Addition Property of Equality

-10/4 = m  Multiplication  Property of Equality

m = = -5/2  0r -2 1/2

In Solving: GOAL is to isolate the variable on one side of the EQ

so as You can read x = its value