SOLUTION: complete each proof given: BC+DE Prove: AB+DE=AC Proof: Statement Reasons BC=DE ___________ __________ Seg. Add. Post. AB+DE=AC

Algebra ->  Geometry-proofs -> SOLUTION: complete each proof given: BC+DE Prove: AB+DE=AC Proof: Statement Reasons BC=DE ___________ __________ Seg. Add. Post. AB+DE=AC       Log On


   



Question 659031: complete each proof
given: BC+DE
Prove: AB+DE=AC
Proof:
Statement Reasons
BC=DE ___________
__________ Seg. Add. Post.
AB+DE=AC ____________


Given: Q is between P and R, R is between Q and S, PR=QS
Prove: PQ=RS


Statements Reasons
Q is between P and R given
PQ+QR=PR ________________
R is between Q ans S ________________
___________________ Seg. Add. Post.
PR=QS ________________
PQ+QR=QR+RS ________________
PQ+QR-QR=QR+RS-QR ________________
_________________ Substitution

I need help please answer by today if you can






Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
1.
given: BC%2BDE
Prove: AB%2BDE=AC
Proof:
Statement -----------------------------Reasons
BC=DE ...........................Definition of Midpoint
AB%2BBC........................... Seg. Add. Post.
AB%2BDE=AC ........................Substitution


2.
Given:Q+is between P and R, R is between Q and S, PR=QS
Prove:PQ=RS
Statements---------------------------------------Reasons
a. Q is between P and R........ given
b. PQ%2BQR=PR................................ segment addition property
c. R is between Q and S.......... given
d. +QR+%2B+RS+=+QR.............................Segment Addition Property
e. PR=QS.................................... given
f. PQ%2BQR=QR%2BRS............................... Substitution
g. PQ%2BQR-QR=QR%2BRS-QR......................... Subtraction Property
h. PQ=RS..................................... Substitution