SOLUTION: if one angle of a triangle is greater than the sum of the other two, show that the triangle is obtuse angle
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-> SOLUTION: if one angle of a triangle is greater than the sum of the other two, show that the triangle is obtuse angle
Log On
Given: ᐃABC
∠A > ∠B + ∠C
∠A + ∠B + ∠C = 180° Sum of the angles of a triangle.
∠B + ∠C < ∠A Reversal property of the given inequality
∠A > 180° - ∠A differences of unequals subtracted from equals
are unequal in the reverse order.
∠A + ∠A > 180° Adding ∠A to both sides (adding =s to =s)
2∠A > 180² 1+1=2
∠A > 90° Equals divided by equals
ᐃABC is an obtuse triangle It has an angle > 90°
Edwin