SOLUTION: Can someone PLEASE help me with this problem? THANK YOU! Let z1 = r1(cos 1 + isin 1) and z2 = r2(cos 2 + isin 2) be two complex numbers. Show that if z2 (doesn't equal to)

Algebra ->  Geometry-proofs -> SOLUTION: Can someone PLEASE help me with this problem? THANK YOU! Let z1 = r1(cos 1 + isin 1) and z2 = r2(cos 2 + isin 2) be two complex numbers. Show that if z2 (doesn't equal to)       Log On


   

Question 615993: Can someone PLEASE help me with this problem? THANK YOU!
Let z1 = r1(cos 1 + isin 1) and z2 = r2(cos 2 + isin 2) be two complex
numbers. Show that if z2 (doesn't equal to) 0, then (z1/z2)=(r1/r2)[cos(1 2) + isin(1 2)].
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Let z1 = r1(cos 1 + isin 1) and z2 = r2(cos 2 + isin 2) be two complex
numbers. Show that if z2 (doesn't equal to) 0, then (z1/z2)=(r1/r2)[cos(1 2) + isin(1 2)].
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z1/z2 = [r1cos(1) + r1isin(1)]/[r2cos(2) + r2isin(2)]
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Multiply numerator and denominator by [r2cos(2)-r2isin(2)] to get:
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z1/z2
= [[r1cos(1) + r1isin(1)][r2cos(2)-r2isin(2)]]/[(r2cos(2))^2 + (r2sin(2))^2]]
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I think I'll let you continue this.
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Cheers,
Stan H.