SOLUTION: Hello! I've been asked by my teacher to solve the following proof:
Prove: If two parallel lines are cut by a transversal, then bisectors of corresponding angles are parallel.
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Prove: If two parallel lines are cut by a transversal, then bisectors of corresponding angles are parallel.
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Question 31170: Hello! I've been asked by my teacher to solve the following proof:
Prove: If two parallel lines are cut by a transversal, then bisectors of corresponding angles are parallel.
I have tried this problem over and over but I cant seem to picture it. Therefore I'm having problems solving it. Please help! Thank You. Found 3 solutions by venugopalramana, cleomenius, Sanjana01:Answer by venugopalramana(3286) (Show Source):
You can put this solution on YOUR website! LET AB AND CD BE THE PARALLEL LINES.LET XY BE A TRANSVERSAL CUTTING AB AT P AND CD AT Q.LET EF BE THE BISECTOR OF ANGLE XPB AND GH THE BISECTOR OF ITS CORRESPONDING ANGLE XQD.
CORRESPONDING ANGLES ARE EQUAL SO..
ANGLE XPB=ANGLE XQD....SINCE EF AND GH ARE THEIR BISECTORS....WE HAVE ....
ANGLE XPF = ANGLE XPB/2 = ANGLE XQD/2 = ANGLE XQH....SO.....
WE HAVE 2 LINES EF AND GH ,A TRANSVERSAL XPQY CUTS THEM AT P AND Q RESPECTIVELY.
AND....ANGLE XPF = ANGLE XQH...WHICH ARE CORRESPONDING ANGLES . HENCE EF IS PARALLEL TO GH.SO THE BISECTORS OF CORRESPONDING ANGLES ARE PARALLEL.
You can put this solution on YOUR website! Let lines AB and CD be parallel lines.
Let transversal EF cross AB and CD.
Let angle 1 and angle 2 be corresponding angles formed by EF crossing lines AB and CD.
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Statement: Angle 1 is congruent to angle 2.
Reason: Theorem, if two parallel lines are cut by a transversal, then each pair of corresponding angles is congruent.
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Statement: 1/2 angle 1 = 1/2 angle 2 (They are congruent).
Reason: Definition of Bisector.
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Statement: The bisectors of angles 1 and angle 2 are parallel.
Reason. Theorem, if 2 lines cut be a tranversal form a pair of corresponding angles with the transversal, then the lines are parallel.
Cleomenius.
You can put this solution on YOUR website! this is what my teacher did -
visit link
https://docs.google.com/drawings/d/1moRQ8lVM61WxX0HoP9x_p5nF-9L2-6wnC3ctyOJTM3k/edit?usp=sharing