SOLUTION: There is a rectangular box that has two right triangles in it. It is given that segmant AB is congruent to segmant CD, and segmant AB is perpendicular to segmant CD. I need to pro

Algebra ->  Geometry-proofs -> SOLUTION: There is a rectangular box that has two right triangles in it. It is given that segmant AB is congruent to segmant CD, and segmant AB is perpendicular to segmant CD. I need to pro      Log On


   

Question 29064: There is a rectangular box that has two right triangles in it. It is given that segmant AB is congruent to segmant CD, and segmant AB is perpendicular to segmant CD. I need to prove that triangle ABC is congruent to triangle CDA.
Found 2 solutions by venugopalramana, cleomenius:
Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
IT IS NOT CLEAR.PLEASE DRAW A FIGURE AND SEND FOR US TO ANSWER.

Answer by cleomenius(959) About Me  (Show Source):
You can put this solution on YOUR website!
I am going to assume you stated the problem incorrectly and meant to state as a given segment AB is parallel to segment CD.
angle A and angle D are right angles, angles of a rectangle are 90 degrees.
Side AB is Congruent to side CD given
Diagonal BC is congruent to diagonal AD. Thereom, the diagonals of rectangle are congruent.
Triangle ABC is congruent to triangle CDA. Hypotenuse Leg theorem.
Cleomenius.