SOLUTION: In triangle PQR, \angle PQR - \\angle RPQ \circ} + \angle RPQ and \angle RSP = 60^\circ + \angle PRS. Find \angle SQR in degrees.

Algebra ->  Geometry-proofs -> SOLUTION: In triangle PQR, \angle PQR - \\angle RPQ \circ} + \angle RPQ and \angle RSP = 60^\circ + \angle PRS. Find \angle SQR in degrees.      Log On


   



Question 1210688: In triangle PQR, \angle PQR - \\angle RPQ \circ} + \angle RPQ and \angle RSP = 60^\circ + \angle PRS. Find \angle SQR in degrees.
Answer by KMST(5428) About Me  (Show Source):
You can put this solution on YOUR website!
Could it be that you meant PQR+-+PRQ+=+34%5Eo++%2B+RPQ
and RSP=60%5Eo+%2B+PRS ,
where each 3 letter string represents the measure of an angle in triangles PQR and PRS?
The 2 equations I wrote would give us some information,
but I cannot do much with that information.
I suspect that a diagram that came with the problem that would give us extra information.
Maybe we would find points P, Q, R, and S going clockwise around one circle, for example.