Question 1210684: In triangle ABC, \angle ABC - \angle ACB = 34^{\circ} + \angle ADB - \angle APB. Find \angle DBC in degrees. Answer by ikleyn(54005) (Show Source):
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In triangle ABC, \angle ABC - \angle ACB = 34^{\circ} + \angle ADB - \angle APB. Find \angle DBC in degrees.
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The condition is either incomplete or incorrect (or BOTH).
Mathematically, this post/(this assignment) makes no sense.
