SOLUTION: Given that ∠FAB≅∠GED and C is the midpoint of AE¯¯¯¯¯, which of the following proves that △ABC≅△EDC? https://thinkwell.cachefly.net/questionbank/95001-96000/956

Algebra ->  Geometry-proofs -> SOLUTION: Given that ∠FAB≅∠GED and C is the midpoint of AE¯¯¯¯¯, which of the following proves that △ABC≅△EDC? https://thinkwell.cachefly.net/questionbank/95001-96000/956      Log On


   



Question 1169211: Given that ∠FAB≅∠GED and C is the midpoint of AE¯¯¯¯¯, which of the following proves that △ABC≅△EDC?
https://thinkwell.cachefly.net/questionbank/95001-96000/95608/img/95608a.svg
A.
1.  ∠FAB≅∠GED (Given)2.  ∠BAC is the supp. of ∠FAB;  ∠DEC is thesupp. of ∠GED (Def. of Supp. ∠s)3.  ∠BAC≅∠DEC (≅ Supp. Thm.)4.  ∠ACB≅∠DCE (Vert. ∠s Thm.)5. C is the midpoint of AE¯¯¯¯¯ (Given)6.  AC¯¯¯¯¯≅EC¯¯¯¯¯ (Def. of mdpt.)7.  △ABC≅△EDC (by ASA Steps 3, 6, 4)

B.
1.  ∠FAB≅∠GED (Given)2.  ∠BAC is the supp. of ∠FAB;  ∠DEC is thesupp. of ∠GED (Def. of Supp. ∠s)3.  ∠BAC≅∠DEC (≅ Supp. Thm.)4.  ∠ACB≅∠DCE (Adj. ∠s Thm.)5. C is the midpoint of AE¯¯¯¯¯ (Given)6.  AC¯¯¯¯¯≅EC¯¯¯¯¯ (Def. of mdpt.)7.  △ABC≅△EDC (by ASA Steps 3, 6, 4)

C.
1.  ∠FAB≅∠GED (Given)2.  ∠BAC is the supp. of ∠FAB;  ∠DEC is thesupp. of ∠DEG (Def. of Supp. ∠s)3.  BC¯¯¯¯¯≅CD¯¯¯¯¯ (≅ Supp. Thm.)4.  ∠ACB≅∠BCE (Vert. ∠s Thm.)5. C is the midpoint of AE¯¯¯¯¯ (Given)6.  BC¯¯¯¯¯≅CD¯¯¯¯¯ (Def. of mdpt.)7.  △ABC≅△EDC (by SAS Steps 3, 1, 6)

D.
1.  ∠FAB≅∠GED (Given)2.  ∠BAC is the supp. of ∠FAB;  ∠DEC is thesupp. of ∠GED (Def. of Supp. ∠s)3.  BC¯¯¯¯¯≅CD¯¯¯¯¯ (≅ Supp. Thm.)4.  ∠ACB≅∠BCE (Vert. ∠s Thm.)5. C is the midpoint of AE¯¯¯¯¯ (Given)6.  BC¯¯¯¯¯≅CD¯¯¯¯¯ (Def. of mdpt.)7.  △ABC≅△EDC (by SAS Steps 3, 1, 6)

Answer by CPhill(1959) About Me  (Show Source):
You can put this solution on YOUR website!
Let's analyze each option to determine which one correctly proves that △ABC≅△EDC.
**Understanding the Diagram and Given Information**
* We are given that ∠FAB≅∠GED.
* C is the midpoint of AE¯¯¯¯¯. This means AC¯¯¯¯¯≅EC¯¯¯¯¯.
* We need to use the given information to prove that △ABC≅△EDC.
**Analyzing Each Option**
* **A.**
* 1. ∠FAB≅∠GED (Given)
* 2. ∠BAC is the supp. of ∠FAB; ∠DEC is the supp. of ∠GED (Def. of Supp. ∠s)
* 3. ∠BAC≅∠DEC (≅ Supp. Thm.)
* 4. ∠ACB≅∠DCE (Vert. ∠s Thm.)
* 5. C is the midpoint of AE¯¯¯¯¯ (Given)
* 6. AC¯¯¯¯¯≅EC¯¯¯¯¯ (Def. of mdpt.)
* 7. △ABC≅△EDC (by ASA Steps 3, 6, 4)
* This option correctly uses the Angle-Side-Angle (ASA) congruence theorem.
* **B.**
* The only difference is that step 4 states ∠ACB≅∠DCE (Adj. ∠s Thm.). Adjacent angles are not necessarily congruent. Vertical angles are. Therefore, this option has an error.
* **C.**
* This option introduces BC¯¯¯¯¯≅CD¯¯¯¯¯ in steps 3 and 6, which is not supported by the given information. Also it tries to use SAS with angles that are not in the correct order.
* Also step 4 says ∠ACB≅∠BCE. Which is incorrect. ∠ACB and ∠DCE are vertical angles.
* **D.**
* This option has the same errors as option C.
**Conclusion**
Option A correctly uses the given information and the ASA congruence theorem to prove that △ABC≅△EDC.
**Final Answer**
The correct answer is A.