SOLUTION: In △MNP, point Q is on side MN so that PM=PQ. Prove that PN>PM.
Algebra.Com
Question 1127227: In △MNP, point Q is on side MN so that PM=PQ. Prove that PN>PM.
Answer by greenestamps(13208) (Show Source): You can put this solution on YOUR website!
What kind of proof do you need?
M, Q, and N are collinear, with Q between M and N.
Triangle QPM is isosceles (PM=PQ).
That makes PN greater than PQ.
If you need a formal proof, it looks as if you can use trigonometry and the law of sines.
If you need a formal two-column proof using Euclidean geometry, I'm not sure how you would do it....
RELATED QUESTIONS
With MN ∥ QP and ∠M ≅ ∠Q, MNPQ is a right trapezoid. Find the following.
m∠P... (answered by greenestamps)
In △ABC, m∠CAB = 60° and point D∈BC so that AD=10 in and the distance... (answered by greenestamps)
In △ABC, m∠CAB = 60° and point D ∈ BC so that AD = 10 in, and the... (answered by ikleyn)
Geometry Proof
Line segment point p point q point r point s on a line segment in... (answered by stanbon)
In quadrilateral LMNT side LM congruent side LT. Bisector of angle MLN intersects, side... (answered by Edwin McCravy)
In a diagram, a square named PQRS is tilted on its side so that vertex Q is on point... (answered by solver91311)
Please can you help solve this probelm? Thanks...
p(-3,4) and q(9,-4) are two points.... (answered by jim_thompson5910)
Prove: if 4 divides mn, then m is even or n is even.
i saw that this was p implies q... (answered by richard1234)
Hello!
Here's my question:
In triangle KLM, P is the midpoint of the line segment LM. (answered by Earlsdon,Thanenjayan)