SOLUTION: If given ABCD is a parallelogram, E bisects AD at E, and F bisects CB at F, prove EG is congruent to GF?

Sorry. You forgot to tell us anything about the point G.

So all we have is this:

 

Where is point G????

We must know where point G is; otherwise, we cannot possibly
prove the theorem.  If you like, you can tell us where G is 
located in the thank-you note form below and we'll get back 
to you by email.

Edwin