Tutors Answer Your Questions about Functions (FREE)
Question 1169186: You can park in a a lot for 15$ an hour for at most 4 hours. A partial hour rounds to the nearest whole hour. find the function, domain and range.
I thought the function was y=15x and the domain was all real numbers.
Click here to see answer by Theo(13342)  |
Question 1169186: You can park in a a lot for 15$ an hour for at most 4 hours. A partial hour rounds to the nearest whole hour. find the function, domain and range.
I thought the function was y=15x and the domain was all real numbers.
Click here to see answer by ikleyn(52747)  |
Question 1169210: βAn airplane is preparing to land at an airport. It is 52200 feet above the ground and is descending at the rate of 3300 feet per minute. At the sameβ airport, another airplane is taking off and will ascend at the rate of 2500 feet per minute. When will the two airplanes be at the same altitude and what will that altitudeβ be?
Click here to see answer by ankor@dixie-net.com(22740)  |
Question 1169162: Ummm... I am wondering now if these second to the last two items which are the table of values in my first activity are functions or not?? Could somebody please solve these for me, thank you so much!! π€
x 2 4 6 8
f(x) 2 6 8 10
x 1 2 3 4
f(x) 1 4 9 16
Click here to see answer by Boreal(15235)  |
Question 1169704: Brandon owes his brother $100. He will repay his brother $5 each week.
Which expression gives the amount in dollars Brandon will still owe his brother after n weeks?
βΆ 5 - 100n
β· 100 - 5n
βΈ 5n - 100
βΉ 100n - 5
Click here to see answer by Boreal(15235)  |
Question 1169998: The problem I got incorrect:
Find inverse of h(x)=(3/4)x+12
My steps...
1) y = (3/4)x+12
2) (4/3)y = x+12
3) (4/3)y-12 = x
4) (4/3)x-12 = y
5) h^-1(x) = (4/3)x-12
Am told correct answer should be h^-1(x) = (4/3)(x-12).
Could someone explain the property I missed applying?
Thank you.
Click here to see answer by josgarithmetic(39613) |
Question 1169998: The problem I got incorrect:
Find inverse of h(x)=(3/4)x+12
My steps...
1) y = (3/4)x+12
2) (4/3)y = x+12
3) (4/3)y-12 = x
4) (4/3)x-12 = y
5) h^-1(x) = (4/3)x-12
Am told correct answer should be h^-1(x) = (4/3)(x-12).
Could someone explain the property I missed applying?
Thank you.
Click here to see answer by MathTherapy(10549)  |
Question 1169998: The problem I got incorrect:
Find inverse of h(x)=(3/4)x+12
My steps...
1) y = (3/4)x+12
2) (4/3)y = x+12
3) (4/3)y-12 = x
4) (4/3)x-12 = y
5) h^-1(x) = (4/3)x-12
Am told correct answer should be h^-1(x) = (4/3)(x-12).
Could someone explain the property I missed applying?
Thank you.
Click here to see answer by greenestamps(13195)  |
Question 1170033: Which of the following relations is a function?
A.
{(5,9),(β7,3),(β5,11),(7,9)}
B.
{(6,11),(β8,7),(6,4),(9,5)}
C.
{(β12,1),(4,9),(β12,8),(β4,15)}
D.
{(8,3),(8,0),(β8,13),(β8,17)}
Click here to see answer by Boreal(15235)  |
Question 1170306: (a) Let f(x): (-inf, 0) U (0 inf) --> R be defined by f(x) = x- (1/x)
Show that f(x) has no inverse function.
(b) Let g(x): (), inf) --> R be defined by gx) = x- (1/x)
Show that g(x) has an inverse function.
I don't understand this. Please help!
Click here to see answer by math_helper(2461)  |
Question 1171008: (a) Let f(x): (-inf, 0) U (0 inf) --> R be defined by f(x) = x- (1/x)
Show that f(x) has no inverse function.
(b) Let g(x): (), inf) --> R be defined by gx) = x- (1/x)
Show that g(x) has an inverse function.
I know I asked this question before, but I didn't really understand the answer, so can you please explain in detail? I don't really get inverse functions. A million thanks for your time.
Click here to see answer by ikleyn(52747)  |
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