Tutors Answer Your Questions about Functions (FREE)
Question 947436: Beyond confused about interval notation.
Say I need to find the domain of: g(x)=√(x+7) - 1/x
So I know I need to set √(x+7)≥0 and then the denominator of -1/x is x>0.
Therefore, the answers would be:
x≥-7 and x>0 ok I understand this far. But interval notation keeps confusing me.
Why is the answer suppose to be -7≤x<0
I know that x≥-7 is the same as -7≤x because for x to be greater than -7 therefore -7 must be ≤x I understand that so -7≤x makes sense but where does the x<0 come from? How can x>0 be the same as x<0 for the answer, How is x greater than zero the same as x less than zero?
Please help
Click here to see answer by josgarithmetic(39618) |
Question 947948: for f(x)=3x^2+5 and g(x)=7x-2,
a)verify:g(x+2)not equal to g(x)+g(2).
b)find(f-g)(x).
c) using the resulting function in (b), show that (f-g)(2)=f(2)-g(2).
d)is (fg)(0)= (f/g)(0)?explain.
e)find f(x+h)-f(x)/h,h is not equal to 0
Click here to see answer by MathLover1(20850)  |
Question 947946: for each planet in a solar system, its year is the time it takes the planet to revolve around the center star.the formula E= 0.2X^3/2 models the number of the earth days in a planet's year,E, where x is the average distance of the planet from the center star,in millions of kilometers. there are approximately 88 Earth days in the year of the planet mercury.What is the average distance of mercury from the star? Round to the nearest million kilometers.clearly state your final answer in a complete sentence.
Click here to see answer by ankor@dixie-net.com(22740)  |
Question 948282: Finding the vertex and x and y intercepts of: G(t)=1/2(t^2-4t)?
I know I can turn this into vertex form like so:
G(t)=1/2(t^2-4t+4)-4
G(t)=1/2(t-2)^2-4
so then the vertex would be
(2,-4) but graphing it online it states that the vertex is:(2,-2) what am I missing here? what makes it a -2 instead of a -4?
Please also explain how to find the x and y intercepts thank you
Click here to see answer by Fombitz(32388)  |
Question 948363: Let f(x) = √(x-4) - 1 and g(x) = (x+1)^2+2x. Find (gºf)(x) and simplify your answer. Final answer should not have any parentheses.
Is my answer correct?
(√(x-4) -1+1)^2 +2(√(x+4) - 1)
= x-4+2√(x-4) + 2
= x+2√(x-4) - 2
^
||
Is this the right answer?
THANKS
Click here to see answer by josgarithmetic(39618) |
Question 949267: Is it possible for x=-2 to be in the Domains of the functions:
a.) R(x)= 3x^3 - 5x + 6 (all over) x + 2
b.)
Explain why or why not for each function. What are the Domains of the functions R(x) and H(x)? If required, use inf for the infinity sign.
Thank You for any help you can provide, I cannot find how to figure out these questions in my notes anywhere so if you can explain how you received each answer that would be great. Thank you again!
Click here to see answer by Theo(13342)  |
Question 949345: Someone help me with this please. I highly appreciated.
A function is given. Determine the average rate of change of the function between the given values of the variable.
f(x) = 5x^2; x = 4, x = 4 + h
Click here to see answer by Theo(13342)  |
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