SOLUTION: h[s(x)] if s(x) = 2^x and h(x) = x^2 A. (2x)^2 B. 4 C. 4x D.x^(2x) E. x^2 F. 2x^2

Algebra ->  Functions -> SOLUTION: h[s(x)] if s(x) = 2^x and h(x) = x^2 A. (2x)^2 B. 4 C. 4x D.x^(2x) E. x^2 F. 2x^2       Log On


   

Question 980054: h[s(x)] if s(x) = 2^x and h(x) = x^2
A. (2x)^2
B. 4
C. 4x
D.x^(2x)
E. x^2
F. 2x^2
Answer by josh_jordan(263) About Me  (Show Source):
You can put this solution on YOUR website!
I'm assuming the question you typed has a typo, and that s(x) = 2x and not 2^x.
h[s(x)] is (2x)^2 because you would plug in 2x for the x in x^2, and the ^2 would apply to 2x and not just to x, which is why F is not the correct answer.

Answer: A