SOLUTION: Determine the domain and range for (x+4)^2+(y+5)^2=25

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Question 949779: Determine the domain and range for (x+4)^2+(y+5)^2=25
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Circle of radius 5, centered at (-4,-5).
Domain is plus and minus 5 within the x value from the center.
Range is plus and minus 5 within the y value from the center.

DOMAIN: -9%3C=x%3C=1

RANGE: -10%3C=y%3C=0