SOLUTION: Please help express in standard form: f(x) = -x^2+6x Vertex? x-intercept? y-intercept? Thank you

Algebra ->  Functions -> SOLUTION: Please help express in standard form: f(x) = -x^2+6x Vertex? x-intercept? y-intercept? Thank you      Log On


   



Question 932974: Please help
express in standard form:
f(x) = -x^2+6x
Vertex?
x-intercept?
y-intercept?
Thank you

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
f(x) = -x^2+6x, x = 0, y-intercept = 0
y = -x^2+6x, y = 0, x-intercept = 6
....
Completing the Square to obtain Vertex Form
f(x) = -(x-3)^2 + 9
V(-3,9)
..........
the vertex form of a Parabola opening up(a>0) or down(a<0),
y=a%28x-h%29%5E2+%2Bk
where(h,k) is the vertex and x = h is the Line of Symmetry