SOLUTION: Give the open interval on which the function is increasing: f(x)=(x-3)^2-2

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Question 918916: Give the open interval on which the function is increasing:
f(x)=(x-3)^2-2
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29=%28x-3%29%5E2-2
it's a parabola, opens upward
first find the vertex- a point where the parabola makes its sharpest turn
k=-2; so,the vertex is at (3,-2)
from f%28x%29=%28x-3%29%5E2-2 we see that h=3
+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+%28x-3%29%5E2-2%29+
the open interval on which the function is increasing:
looking at the vertex, parabola increasing from x=3 to infinity
so, interval is:
(3,infinity)