SOLUTION: Suppose {{{ y = 2x^2 + x - 16 }}} Find the following information for this function. The coordinates of the Vertex are ( _ , _ ). This parabola has ( _

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Question 906321: Suppose

Find the following information for this function.
The coordinates of the Vertex are ( _ , _ ).
This parabola has ( __ ) x-intercepts.
These intercepts occur at (exact values):
x = ( __ ) Smaller value
x = ( __ ) Bigger value
Enter DNE in any unused spaces.
This parabola attains a __ value of __
Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website!

y = 2(x+1/4)^2 - 1/8 - 16
y = 2(x+.25)^2 - 129/8
0 = 2(x+.25)^2 - 129/8
129/16 = (x+.25)^2
-.25 � sqrt(129/16) = x
x is 2.5895, -3.0895
The coordinates of the Vertex are ( .25, -129/8).
This parabola has (2 ) x-intercepts.
These intercepts occur at (exact values):
x = (-.25 - √129/4) Smaller value
x = (-.25 +√129/4 ) Bigger value
This parabola attains a min value of -129/8

SOLUTION: Suppose {{{ y = 2x^2 + x - 16 }}} Find the following information for this function. The coordinates of the Vertex are ( _ , _ ). This parabola has ( __ ) x-intercepts.