SOLUTION: Find domain of the function. Please explain:
√(x+3) / (x - 6)
My attempt:
√(x+3) > 0 then x=-3. the √ is canceled out?
then
x-6>0 then x= 6
So then
Algebra ->
Functions
-> SOLUTION: Find domain of the function. Please explain:
√(x+3) / (x - 6)
My attempt:
√(x+3) > 0 then x=-3. the √ is canceled out?
then
x-6>0 then x= 6
So then
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Question 905508: Find domain of the function. Please explain:
√(x+3) / (x - 6)
My attempt:
√(x+3) > 0 then x=-3. the √ is canceled out?
then
x-6>0 then x= 6
So then domain: [-3,6]
Is this right?
Thank you Found 2 solutions by ewatrrr, Fombitz:Answer by ewatrrr(24785) (Show Source):
