SOLUTION: I don't know how to use the quadratic formula to solve this problem 2x^2=7x-3

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Question 897045: I don't know how to use the quadratic formula to solve this problem
2x^2=7x-3

Found 2 solutions by rothauserc, MathTherapy:
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
2x^2 = 7x-3
2x^2 -7x +3 = 0
the quadratic formula is x = (-b +or- square root (b^2 -4ac))/ 2a and standard form for quadratic is ax^2 +bx +c = 0
now we can solve our equation
x = (7 + square root(7^2 -4*2*3))/(2*2) = 8.25
x = (7 - square root(7^2 -4*2*3))/(2*2) = 5.75
therefore x = 8.25 or 5.75

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

I don't know how to use the quadratic formula to solve this problem

2x^2=7x-3
2x%5E2+-+7x+%2B+3+=+0
highlight_green%28x+=+system%28%281%2F2%29or%2C+3%29%29