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Question 887077: The distance traveled by a ball rolling down a ramp is given by s(t)=2.25t^2, where t is the time in seconds after the ball is released, and s(t) is measured in feet. Evaluate the average velocity of the ball for the time interval [1.0,1.1].
Please show me your work in this problem, Thank you!
Found 2 solutions by stanbon, rothauserc:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The distance traveled by a ball rolling down a ramp is given by s(t)=2.25t^2, where t is the time in seconds after the ball is released, and s(t) is measured in feet. Evaluate the average velocity of the ball for the time interval [1.0,1.1].
Please show me your work in this problem, Thank you!
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Average Velocity = [s(1.1)-s(1)]/[1.1-1]
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= [2.25(1.1^2) - 2.25(1^2)]/[0.1]
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= [2.25(0.21)]/0.1
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= 4.725
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Cheers,
Stan H.
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Answer by rothauserc(4718)  (Show Source):
You can put this solution on YOUR website! Using given formula calculate the distance covered at t=1.0 and t=1.1, then subtract s(1.0) from s(1.1)
s(1.1) = 2.25*(1.1)^2 = 2.7225
s(1.0) = 2.25*(1.0)^2 = 2.25
s(1.1) - s(1.0) = 0.4725
average velocity(Va) equals (delta distance) / (delta time)
Va = 0.4725 / 0.1 = 4.725
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