Question 883235: find the equation of the quadratic function whose graph has the vertex (0,2) and contains the point (1,3) Answer by LinnW(1048) (Show Source):
You can put this solution on YOUR website! Since the vertex is (0,2)
our equation has the form y = ax^2 + 2
using the point (1,3) for (x,y)
y = ax^2 + 2 becomes 3 = a*1^2 +2
3 = a*1 + 2
3 = a + 2
add -2 to each side
1 = a
So our equation is y = 1*x^2 +2
or y = x^2 + 2
