SOLUTION: I need help figuring out how to find the domain and range of a function in vertex form. For example y= 1.75(x+3)^2+3
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Question 829966: I need help figuring out how to find the domain and range of a function in vertex form. For example y= 1.75(x+3)^2+3 Found 2 solutions by LinnW, TimothyLamb:Answer by LinnW(1048) (Show Source):
You can put this solution on YOUR website! Look for values of x which will cause division by zero.
Look for values of x which will cause square root of a negative number.
Eliminate these values of x from the domain.
If x values have been eliminated from the domain,
consider the possible values that y can take for values of x that remain in the domain.
This will determine the range.
You can put this solution on YOUR website! ---
y = 1.75(x + 3)^2 + 3
y = 1.75(x + 3)(x + 3) + 3
y = 1.75(x^2 + 6x + 9) + 3
y = 1.75x^2 + 1.75*6x + 1.75*9 + 3
y = 1.75x^2 + 10.5x + 15.75 + 3
y = 1.75x^2 + 10.5x + 18.75
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the above quadratic equation is in standard form, with a=1.75, b=10.5, and c=18.75
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
1.75 10.5 18.75
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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the quadratic vertex is a minimum at: ( x= -3, y= 3 )
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answer:
the domain is all x real
the range is y >= 3
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graph:
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Solve and graph linear equations:
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Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
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Solve systems of linear equations up to 6-equations 6-variables:
https://sooeet.com/math/system-of-linear-equations-solver.php
