SOLUTION: Please help me sketch {{{ g(x)=-sqrt(16-3x) }}} by first determining the axial intercepts and asymptotes. Thank you

g(x) = -√16-3x

There are no asymptotes, since there are no denominators with variables.

y = -√16-3x

Find the y intercept by substituting 0 for x:

y = -√16-3(0)

y = -√16

y = -4

So the y-intercept is (0,-4)

Find the x-intercept by substituting 0 for y

0 = -√16-3x

Square both sides

 0 = 16-3x

3x = 16 

 x = 

So the x intercept is (,0) or (,0)



Maybe we need a few more points

 x|y
 5|-1
-3|-5
 2|-3.6
 4|-2
-5|-5.6



Now we can sketch it:



Notice that it is the bottom half of a parabola:.  The top half of the
parabola, the dotted part below, has the equation y = +√16-3x.  It takes 
two separate equations to get the graph of the whole parabola:





Edwin