SOLUTION: 1. This equation is given in vertex form, write it in standard form. f(x)= -(3/4)(x+2)^2 +8 2. Convert each quadratic function to vertex form by completing the square. a)y=x^2

Algebra ->  Functions -> SOLUTION: 1. This equation is given in vertex form, write it in standard form. f(x)= -(3/4)(x+2)^2 +8 2. Convert each quadratic function to vertex form by completing the square. a)y=x^2      Log On


   

Question 821147: 1. This equation is given in vertex form, write it in standard form.
f(x)= -(3/4)(x+2)^2 +8
2. Convert each quadratic function to vertex form by completing the square.
a)y=x^2-9x+3
b)y= -2x^2+28x-7
3.Determine the vertex of the quadratic function.
y=-24x^2+18x+11
-state the axis of symmetry
-the miminum or maximum value
-the domain and range

Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
That is a misunderstanding.
Vertex form IS standard form.
You could put #1 into GENERAL form through multiplying and simplifying.
f%28x%29=-%283%2F4%29%28x%5E2%2B4x%2B8%29%2B8
f%28x%29=%28-3%2F4%29x%5E2-3x-6%2B8
highlight_green%28f%28x%29=%28-3%2F4%29x%5E2-3x%2B2%29

#2,
Only a small amount of help to start with #b,
Factor the right hand side:
y=-2%28x%5E2-14x%2B7%2F2%29
The missing square piece is %28-14%2F2%29%5E2=49;
ADD and SUBTRACT 49 INSIDE the parenthesised quadratic expression, and simplify but adjusting the form into a%28x-h%29%5E2%2Bk;
Can you perform the necessary steps or do you still need help?