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Question 715954: in the problem h(x)=x^2+2x-3, i know the domain is all real numbers, but how come the range is [-4,to infinity). how do I find the range of the problem?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! in the problem h(x)=x^2+2x-3, i know the domain is all real numbers, but how come the range is [-4,to infinity). how do I find the range of the problem?
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Since the vertex is either at the bottom or at the top of the range,
find the vertex.
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x = -b/(2a) = -2/(2*1) = -1
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f(-1) = (-1)^2 +2(-1)-3 = 1-2-3 = -4
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Since "a" is positive the parabola opens up,
so -4 is the lowest y-value.
Range: [-4,+oo)
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Cheers,
Stan H.
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