SOLUTION: Solve using the substitution method.
2x-2y=7
x=y+5
2(y+5)-2y=7
2y+10-2y=7
-10 -10
2y-2y=-3
0=-3
OR if I cancel out the variables first I get 1
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-> SOLUTION: Solve using the substitution method.
2x-2y=7
x=y+5
2(y+5)-2y=7
2y+10-2y=7
-10 -10
2y-2y=-3
0=-3
OR if I cancel out the variables first I get 1
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Question 675304: Solve using the substitution method.
2x-2y=7
x=y+5
2(y+5)-2y=7
2y+10-2y=7
-10 -10
2y-2y=-3
0=-3
OR if I cancel out the variables first I get 10=7
Obviously, neither of these is right, so what am I doing wrong?
Thanks,
Mandie
You can put this solution on YOUR website! 2x - 2y = 7
x = y+5
2(y+5) - 2y = 7
2y + 10 - 2y = 7
10 = 7
There is no solution.
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You haven't done anything wrong, the lines don't intersect anywhere, they are parallel with the same slope of 1.
2x-2y = 7 | 2x-7=2y |
x = y + 5 |
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