SOLUTION: Let the function f be defined by f(x)=x^2-7x+10 and f(t+1)=0, what is one possible value of t?

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Question 665542: Let the function f be defined by f(x)=x^2-7x+10 and f(t+1)=0, what is one possible value of t?
Answer by bloggauta(8) About Me  (Show Source):
You can put this solution on YOUR website!
f(x)= x^2-7x+10 and f(t+1)= 0
f(t+1)= (t+1)^2-7(t+1)+10= 0
t^2+2t+1-7t-7+10= 0
t^2-5t+4= 0 → (t-4)(t-1)= 0
t= 4 or t= 1