What is the value of g[f(3)] for the functions f(x) = 3x – 5 and g(x) = x + 1?
I won't do it for you. Instead I'll do one exactly like this one,
and just change the numbers:
What is the value of g[f(4)] for the functions f(x) = 4x – 7 and g(x) = x + 3?
First find f(4) by substituting x=4 in f(x) = 4x - 7
f(x) = 4x - 7
f(4) = 4(4) - 7
f(4) = 16 - 7
f(4) = 9
Now g[f(4)] is equal to g(9). So we find g(9) by substituting x=9
in g(x) = x + 3.
g(x) = x + 3
g(9) = 9 + 3
g(9) = 12.
So g[f(4)] = g(9) = 12.
Do yours the exact same way.
-----------------------------------------------------
Change the given equation into slope-intercept form. 3x + 4y = 12
I'll do this one instead:
Change the given equation into slope-intercept form. 4x + 5y = 20
4x + 5y = 20
5y = -4x + 20
Divide every term by 5
=
x +
y =
x + 4
Do yours the exact same way.
Edwin