You can
put this solution on YOUR website!
(4x3yz4)(2xy-2z-1)(5x-2y-2z3)
Give the y in the 1st factor and the x in the
2nd factor an exponent of 1:
(4x3y1z4)(2x1y-2z-1)(5x-2y-2z3)
Multiply the coefficients
4 = 40
Multiply the x's by adding up the exponents
x3x1x-2 = x3+1-2 = x2
Multiply the y's by adding up the exponents
y1y-2y-2 = y1-2-2 = y-3
Multiply the z's by adding up the exponents
z4z-1z3 = z4-1+3 = z6
So you have
40x2y-3z6
The probably want you to use only positive
exponents, so move they y-3 from the
numerator to the denominator as y3
40x2z6
棗棗棗棗
y3
Edwin