SOLUTION: Good dayy please help me with this problem. sorry for my bad english The line tangent to the graph of f( x) = 1/(3x-2) in x = 0 what would be the equation thanks

Algebra ->  Functions -> SOLUTION: Good dayy please help me with this problem. sorry for my bad english The line tangent to the graph of f( x) = 1/(3x-2) in x = 0 what would be the equation thanks      Log On


   

Question 637444: Good dayy
please help me with this problem. sorry for my bad english
The line tangent to the graph of f( x) = 1/(3x-2) in x = 0
what would be the equation
thanks
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,



f(x) = 1/(3x-2)     f%280%29+=+-1%2F2

f '(x) = %283x-2%29%2A0+-+1%2A3%2F%283x-2%29%5E2    ||Quotient Rule

f '(0) = -3/4 = m, the slope of the tangent line at x = 0

y = mx + b

y = (-3/4)x + b    |\using Pt(0,-1/2) to find b

-1/2 = b

y = (-3/4)x -1/2  the EQ of the tangent line