SOLUTION: The domain of the function f is {x: -1 < x < 5}. If g(x) = 2f(-x), what is the domain of the function g? i know that the answer is (-5 < x < 1) but I am curious about the step

Algebra ->  Functions -> SOLUTION: The domain of the function f is {x: -1 < x < 5}. If g(x) = 2f(-x), what is the domain of the function g? i know that the answer is (-5 < x < 1) but I am curious about the step      Log On


   



Question 633882: The domain of the function f is {x: -1 < x < 5}. If g(x) = 2f(-x), what is the domain of the function g?

i know that the answer is (-5 < x < 1) but I am curious about the steps necessary to get that answer

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
For x such that -5%3Cx%3C1, then 5%3E-x%3E-1, which is the same as -1%3C-x%3C5, so (-x) is in the domain of f(x).
Therefore, f(-x) is defined, and can be calculated and multiplied times 2 to find g(x).
For example, g%28-4%29=2%2Af%284%29 exists, and so does g%280.7%29=2%2Af%28-0.7%29.

On the other hand, when x%3C=-5, then -x%3E=5,and
(-x) is out of the domain of f(x).
For x%3E=1, -x%3C=-1 is outside the domain of f(x).
In either case case f(-x) does not exist, and neither does g(x).
For example for x=-5, g%28-5%29=2%2Af%285%29 does not exist. It is not defined.
The same goes for x=1. In that case, g%281%29=2%2Af%28-1%29 does not exist either.

The function f(x) could be simply defined as f(x)=8 for x such that -1 If you like a fancier function, an example could be
f%28x%29=1%2Fsqrt%28%28x%2B1%29%285-x%29%29