SOLUTION: Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). f(x)=1/2(x+3)^2+6
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Question 581648
:
Find the vertex, the line of symmetry, and the maximum or minimum value of f(x).
f(x)=1/2(x+3)^2+6
Answer by
jim_thompson5910(35256)
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Hint: The equation
has the vertex (h,k), the line of symmetry of x = h, and one of the following is possible
i) if a > 0, then f(x) = k is the minimum
OR
ii) if a < 0, then f(x) = k is the maximum