SOLUTION: rewrite 3x+4y=15+6y so that y is a funtion of x

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Question 58058This question is from textbook Algebra 1
: rewrite 3x+4y=15+6y so that y is a funtion of x This question is from textbook Algebra 1

Found 3 solutions by rcmcc, Earlsdon, tutorcecilia:
Answer by rcmcc(152) About Me  (Show Source):
You can put this solution on YOUR website!
y=f(x)
so if you isolate y you get the equation f(x)
3x+4y=15+6y
place the y variables to one side
3x=15+2y
remove the 15 from the y by subtraction
3x-15=2y
divide by 2 to isolate y
(3/2)x-(15/2)=y
so f(x)=(3/2)x-(15/2)

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Rewrite: 3x%2B4y+=+15%2B6y so that y is a function of x.
This means that you must solve the equation for y, and, if required, replace the y with f(x).
3x%2B4y+=+15%2B6y Subtract 4y from both sides of the equation.
3x+=+15%2B2y Now subtract 15 from both sides.
3x-15+=+2y Finally, divide both sides by 2.
%283%2F2%29x+-+15%2F2+=+y which you can rewtite as:
y+=+%283%2F2%29x+-+15%2F2 or in function form as:
f%28x%29+=+%283%2F2%29x+-+15%2F2

Answer by tutorcecilia(2152) About Me  (Show Source):
You can put this solution on YOUR website!
3x+4y=15+6y
3x+4y-6y=15+6y-6y
3x-2y=15
3x-3x-2y=-3x+15
-2y=-3x+15
-2y/-2=-3/-2x+15/-2
y=3/2x-15/2