SOLUTION: natural domain of the square root of 5+4x-x^2

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Question 578188: natural domain of the square root of 5+4x-x^2
Answer by ad_alta(240) About Me  (Show Source):
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5+4x-x^2=-(x-5)(x+1) must be greater than or equal to zero, so the we solve 5+4x-x^2>=0 to get -1 <= x <= 5.