SOLUTION: I need help understanding how {{{ (x+1)^3(x-4)(x-0) }}} is equal to {{{ x^5-x^4-9x^3-11x^2-4x }}} I've tried to figure out how that is the answer but the factor with the multipi

Algebra ->  Functions -> SOLUTION: I need help understanding how {{{ (x+1)^3(x-4)(x-0) }}} is equal to {{{ x^5-x^4-9x^3-11x^2-4x }}} I've tried to figure out how that is the answer but the factor with the multipi      Log On


   



Question 576349: I need help understanding how +%28x%2B1%29%5E3%28x-4%29%28x-0%29+ is equal to +x%5E5-x%5E4-9x%5E3-11x%5E2-4x+
I've tried to figure out how that is the answer but the factor with the multipilicty of 3 throws me off. Please help me, thank you!

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!





Is the part. Then just multiply the result above by each of the other two factors. Note is just

In general, the binomial expansion is:



Where is the number of combinations of things taken at a time and is calculated by

John

My calculator said it, I believe it, that settles it
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