s = 3t + 1
find the range of the function if
the domain is {-3,0,3}
Plug in the -3 for t.
s = 3t + 1
s = 3(-3) + 1
s = -9 + 1
s = -8
So -8 is one member of the range.
Plug in the 0 for t.
s = 3t + 1
s = 3(0) + 1
s = 0 + 1
s = 1
So 1 is another member of the range.
Plug in the 3 for t.
s = 3t + 1
s = 3(3) + 1
s = 9 + 1
s = 10
So 10 is the last member of the range.
So the range is {-8, 1, 10}
That wasn't very hard, was it?
Edwin