SOLUTION: determine domain of : y = square root of (x^2-16)

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Question 50214: determine domain of :
y = square root of (x^2-16)
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
determine domain of :
y = square root of (x^2-16)
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Since you want "y" to be a Real Number,
x^2-16 must be greater than or equal to zero.
x^2-16>=0
x^2>=16
x>=4 ; x<=-4
That is the domain.
Cheers,
Stan H.