SOLUTION: the distance between the points (x,8) and (3,4) is 5 units. Then x is

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Question 485840: the distance between the points (x,8) and (3,4) is 5 units. Then x is
Found 2 solutions by Jstrasner, MathTherapy:
Answer by Jstrasner(112) About Me  (Show Source):
You can put this solution on YOUR website!
Hey,
So for this problem we need to use the pythagorean theorem to discover what x is.
First, we need to plot the triangle that the two points are making:
First, the 8 and the 4 are the y measurements of the triangle, so if you subtract 4 from 8 you get 4. So we know that the measurement of the y leg is 4.
Second, the pythagorean theorem says that z^2 = x^2 + y^2
We know what the z and the y are: z=5 and y=4. So if we plug them into the equation we get:
5^2 = x^2 + 4^2 => 25 = x^2 + 16 => 9 = x^2 => x = 3
So if the x measurement is 3 then the x coordinate in the point must be 3 units away from (3,4) along the x axis. So the x coordinate is 3 + 3 = 6
Therefore, x = 6
It may be a little confusing but just plot out the triangle and use the pythagorean theorem, where the two short legs of the right triangle are the x and y and the long side, or the hypotenuse, is the z.
I hope this helps!

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
the distance between the points (x,8) and (3,4) is 5 units. Then x is

Distance between these 2 points is 5 units

Using distance formula: D+=+sqrt%28%28x%5B2%5D-x%5B1%5D%29%5E2+%2B+%28y%5B2%5D-y%5B1%5D%29%5E2%29, and with D = 5, x%5B2%5D+=+3, x%5B1%5D+=+x, y%5B2%5D+=+4, and y%5B1%5D+=+8, we get:

5+=+sqrt%28%283+-+x%29%5E2+%2B+%284+-+8%29%5E2%29 ------ 5+=+sqrt%289+-+6x+%2B+x%5E2+%2B+%28-+4%29%5E2%29 ---- 5+=+sqrt%28x%5E2+-+6x+%2B+25%29

5%5E2+=+%28sqrt%28x%5E2+-+6x+%2B+25%29%29%5E2 ------- Squaring both sides of equation

25+=+x%5E2+-+6x+%2B+25 ------- x%5E2+-+6x+=+0
x(x – 6) = 0

x = 0, or x – 6 = 0
x = 0, or x = 6

Therefore, x = highlight_green%280_or_6%29

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Check
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I believe you can do this!! If not, just use 0 in place of x in the ordered pair, then plug in each value into the distance formula to see if the distance is 5 units, as given.

Then use 6 in place of x in the ordered pair, plug in each value into the distance formula to see if the distance is 5 units, as given.

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