SOLUTION: k^-1(x) when k(x) = x^2+5

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Question 484177: k^-1(x) when k(x) = x^2+5
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
k^-1(x) when k(x) = x^2+5
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y = x^2+5
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1st: Interchange x and y to get:
x = y^2+5
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2nd: Solve for "y":
y^2 = x-5
y = sqrt(x-5)
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Cheers,
Stan H.