SOLUTION: x²+14 how many solutions does it have?

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Question 473478: x²+14 how many solutions does it have?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
From x%5E2%2B14 we can see that a=1, b=0, and c=14


D=b%5E2-4ac Start with the discriminant formula.


D=%280%29%5E2-4%281%29%2814%29 Plug in a=1, b=0, and c=14


D=0-4%281%29%2814%29 Square 0 to get 0


D=0-56 Multiply 4%281%29%2814%29 to get %284%29%2814%29=56


D=-56 Subtract 56 from 0 to get -56


So the discriminant is D=-56


Since the discriminant is less than zero, this means that there are two complex solutions.


In other words, there are no real solutions.