SOLUTION: Trains A and B are traveling the same direction on parrarel lines. Train A is traveling 100 mph and train B is traveling 120 mph. Train A passes the station at 5:25 am and train B
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Question 452348: Trains A and B are traveling the same direction on parrarel lines. Train A is traveling 100 mph and train B is traveling 120 mph. Train A passes the station at 5:25 am and train B passes station at 5:37 am, what time will train B catch up with train A? Found 2 solutions by ankor@dixie-net.com, htmentor:Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Trains A and B are traveling the same direction on parallel lines.
Train A is traveling 100 mph and train B is traveling 120 mph.
Train A passes the station at 5:25 am and train B passes station at 5:37 am, what time will train B catch up with train A?
:
From the given information, we know that Train B is 12 min behind A at at 5:25 pm
therefore Train B is: * 120 = 24 miles behind Train A at that time.
:
Let t = time required for Train B to catch Train A
:
Write a distance equation; dist = speed * time
:
Train B dist = Train A dist + 24 mi
120t = 100t + 24
120t - 100t = 24
20t = 24
t =
t = 1.2 hrs for B to catch A
:
Convert 1.2 hrs to hrs and minutes: 1 + .2(60) = 1 hr 12 min
:
Find the time from 5:25 pm:
5:25 + 1:12 = 6:37 pm, Train B catches Train A
You can put this solution on YOUR website! Trains A and B are traveling the same direction on parrarel lines. Train A is traveling 100 mph and train B is traveling 120 mph. Train A passes the station at 5:25 am and train B passes station at 5:37 am, what time will train B catch up with train A?
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The relative speed of the two trains is 120 - 100 = 20 mph
Train A has a 12 min. head start. In that time train A traveled 100 mph * 1/5 hr = 20 miles
Since the relative speed is 20 mph, if train A were standing still train B would
approach train A at 20 mph. The time required to travel 20 miles at 20 mph is:
20 mi/20 mi/hr = 1 hr.
So they meet at 6:37 am