SOLUTION: How do you graph y=-1/2x to the third power?

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Question 387503: How do you graph y=-1/2x to the third power?
Answer by Jk22(389) About Me  (Show Source):
You can put this solution on YOUR website!
let y(x)=-1/2x^3

behaviour at infinity :

x->+00 => y->-oo
x->-oo => y->+oo

y'(x)=-3/2x^2

y'=0 => x=0 => stationary point at x=0, y=0

y''(0)=-3x => saddle point at x=0

hence the graph is :
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+-1%2F2%2Ax%5E3%29+