SOLUTION: Thank you so much!!
Write an equation of the line containing the given point and parallel to the given line. Express in y = mx+b.
(-6,2;) 6x = 5y+4
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-> SOLUTION: Thank you so much!!
Write an equation of the line containing the given point and parallel to the given line. Express in y = mx+b.
(-6,2;) 6x = 5y+4
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Question 375863: Thank you so much!!
Write an equation of the line containing the given point and parallel to the given line. Express in y = mx+b.
(-6,2;) 6x = 5y+4 Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Write an equation of the line containing the given point and parallel to the given line.
Express in y = mx+b.
(-6,2;) 6x = 5y+4
:
Find the slope of the given equation, put it in the slope intercept form y = mx+b:
6x = 5y + 4
-5y = -6x + 4
y has to be positive, multiply by -1
5y = 6x - 4
divide by 5
y = x -
:
The slope = , a parallel line will have the same slope
Use the point/slope form y - y1 - m(x - x1)
:
y - 2 = (x - (-6))
y - 2 = (x + 6)
y - 2 = x +
y = x + + 2
y = x + +
y = x + ; is the parallel line
