SOLUTION: Given f (x)= x2-10x/x3-x+20, find f (-1)

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Question 328193: Given f (x)= x2-10x/x3-x+20, find f (-1)
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
f (x)= x^2-10x/x^3-x+20,
find f (-1)
f(-1)=-1^2-10*-1/-1^3-(-1)+20
f(-1)=1+10/-1+1+20
f(-1)=11/20 ans.