SOLUTION: This is a word problem. The area of rectangle is 250 square inches. The length of the rectangle is 5 less than 3 times the width. Show the equation that will find the width and

Algebra ->  Functions -> SOLUTION: This is a word problem. The area of rectangle is 250 square inches. The length of the rectangle is 5 less than 3 times the width. Show the equation that will find the width and       Log On


   

Question 319342: This is a word problem.
The area of rectangle is 250 square inches. The length of the rectangle is 5 less than 3 times the width. Show the equation that will find the width and then use this equation to find the length and width or the rectangle.
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
AreaOfRectangle+=+Length+%2A+Width
Let W be the Width. You are told Length+=+3W+-5
And also told the area is 250. So
250+=+%283W-5%29+%2A+W
250+=+3w%5E2+-+5W
0+=+3W%5E2+-+5W+-+250
0+=+%283W+%2B+25%29%28W+-+10%29
For a product to be 0, either (3W+25) = 0 or (W-10)=0
So
3W%2B25=0
W=+-25%2F3 Since the width cannot be a negative number, this is not a solution
Now check
W-10+=0
W+=+10
If W = 10, then Length = 3W-5 = 30-5 = 25
The dimensions are 25x10